Base | Representation |
---|---|
bin | 11110101110000010101… |
… | …010000111011101001011 |
3 | 21110210220200111001211212 |
4 | 132232002222013131023 |
5 | 234041332340133003 |
6 | 4253442322443335 |
7 | 305342032420106 |
oct | 36560252073513 |
9 | 7423820431755 |
10 | 2111021021003 |
11 | 744308372104 |
12 | 2a116880354b |
13 | 1240b744b4cb |
14 | 742614d373d |
15 | 39da4a59dd8 |
hex | 1eb82a8774b |
2111021021003 has 2 divisors, whose sum is σ = 2111021021004. Its totient is φ = 2111021021002.
The previous prime is 2111021020967. The next prime is 2111021021017. The reversal of 2111021021003 is 3001201201112.
It is an a-pointer prime, because the next prime (2111021021017) can be obtained adding 2111021021003 to its sum of digits (14).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2111021021003 - 220 = 2111019972427 is a prime.
It is a super-2 number, since 2×21110210210032 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2111021021033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055510510501 + 1055510510502.
It is an arithmetic number, because the mean of its divisors is an integer number (1055510510502).
Almost surely, 22111021021003 is an apocalyptic number.
2111021021003 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111021021003 is an equidigital number, since it uses as much as digits as its factorization.
2111021021003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 2111021021003 its reverse (3001201201112), we get a palindrome (5112222222115).
The spelling of 2111021021003 in words is "two trillion, one hundred eleven billion, twenty-one million, twenty-one thousand, three".
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