Base | Representation |
---|---|
bin | 11110101110000010101… |
… | …101111011001001111001 |
3 | 21110210220202100210002212 |
4 | 132232002231323021321 |
5 | 234041333114103233 |
6 | 4253442400104505 |
7 | 305342044045223 |
oct | 36560255731171 |
9 | 7423822323085 |
10 | 2111022019193 |
11 | 74430899405a |
12 | 2a1169005135 |
13 | 1240b770a959 |
14 | 742616b3413 |
15 | 39da4ba5a48 |
hex | 1eb82b7b279 |
2111022019193 has 2 divisors, whose sum is σ = 2111022019194. Its totient is φ = 2111022019192.
The previous prime is 2111022019153. The next prime is 2111022019201. The reversal of 2111022019193 is 3919102201112.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1385027704384 + 725994314809 = 1176872^2 + 852053^2 .
It is a cyclic number.
It is not a de Polignac number, because 2111022019193 - 222 = 2111017824889 is a prime.
It is a super-4 number, since 4×21110220191934 (a number of 50 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (2111022019153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055511009596 + 1055511009597.
It is an arithmetic number, because the mean of its divisors is an integer number (1055511009597).
Almost surely, 22111022019193 is an apocalyptic number.
It is an amenable number.
2111022019193 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111022019193 is an equidigital number, since it uses as much as digits as its factorization.
2111022019193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 32.
The spelling of 2111022019193 in words is "two trillion, one hundred eleven billion, twenty-two million, nineteen thousand, one hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •