211110312123131 has 4 divisors (see below), whose sum is σ = 211113555598200. Its totient is φ = 211107068648064.

The previous prime is 211110312123101. The next prime is 211110312123163. The reversal of 211110312123131 is 131321213011112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-211110312123131 is a prime.

It is a super-2 number, since 2×211110312123131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 211110312123097 and 211110312123106.

It is not an unprimeable number, because it can be changed into a prime (211110312123101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1621639901 + ... + 1621770078.

It is an arithmetic number, because the mean of its divisors is an integer number (52778388899550).

Almost surely, 2^{211110312123131} is an apocalyptic number.

211110312123131 is a deficient number, since it is larger than the sum of its proper divisors (3243475069).

211110312123131 is an equidigital number, since it uses as much as digits as its factorization.

211110312123131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3243475068.

The product of its (nonzero) digits is 216, while the sum is 23.

Adding to 211110312123131 its reverse (131321213011112), we get a palindrome (342431525134243).

The spelling of 211110312123131 in words is "two hundred eleven trillion, one hundred ten billion, three hundred twelve million, one hundred twenty-three thousand, one hundred thirty-one".