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211111123141 is a prime number
BaseRepresentation
bin1100010010011100110…
…1000001100011000101
3202011220200211020000201
43010213031001203011
511424323421420031
6240552204010501
721152346640012
oct3044715014305
9664820736021
10211111123141
11815937a84a6
1234ab8830a31
1316ba5283159
14a309a3a709
155758b63d61
hex31273418c5

211111123141 has 2 divisors, whose sum is σ = 211111123142. Its totient is φ = 211111123140.

The previous prime is 211111123127. The next prime is 211111123189. The reversal of 211111123141 is 141321111112.

It is a m-pointer prime, because the next prime (211111123189) can be obtained adding 211111123141 to its product of digits (48).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 210723230116 + 387893025 = 459046^2 + 19695^2 .

It is a cyclic number.

It is not a de Polignac number, because 211111123141 - 211 = 211111121093 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211111123541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105555561570 + 105555561571.

It is an arithmetic number, because the mean of its divisors is an integer number (105555561571).

Almost surely, 2211111123141 is an apocalyptic number.

It is an amenable number.

211111123141 is a deficient number, since it is larger than the sum of its proper divisors (1).

211111123141 is an equidigital number, since it uses as much as digits as its factorization.

211111123141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 48, while the sum is 19.

Adding to 211111123141 its reverse (141321111112), we get a palindrome (352432234253).

The spelling of 211111123141 in words is "two hundred eleven billion, one hundred eleven million, one hundred twenty-three thousand, one hundred forty-one".