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2111131420201 = 5479938524999
BaseRepresentation
bin11110101110001001001…
…111010000011000101001
321110211012101012221002001
4132232021033100120221
5234042044120421301
64253501305011001
7305344542663466
oct36561117203051
97424171187061
102111131420201
11744364716711
122a1199783a61
1312410429348b
147427203066d
1539dae5b5c01
hex1eb893d0629

2111131420201 has 4 divisors (see below), whose sum is σ = 2111170000000. Its totient is φ = 2111092840404.

The previous prime is 2111131420183. The next prime is 2111131420253. The reversal of 2111131420201 is 1020241311112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2111131420201 - 25 = 2111131420169 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2111131420501) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19207701 + ... + 19317298.

It is an arithmetic number, because the mean of its divisors is an integer number (527792500000).

Almost surely, 22111131420201 is an apocalyptic number.

It is an amenable number.

2111131420201 is a deficient number, since it is larger than the sum of its proper divisors (38579799).

2111131420201 is an equidigital number, since it uses as much as digits as its factorization.

2111131420201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38579798.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 2111131420201 its reverse (1020241311112), we get a palindrome (3131372731313).

The spelling of 2111131420201 in words is "two trillion, one hundred eleven billion, one hundred thirty-one million, four hundred twenty thousand, two hundred one".

Divisors: 1 54799 38524999 2111131420201