2111131420253 has 2 divisors, whose sum is σ = 2111131420254. Its totient is φ = 2111131420252.

The previous prime is 2111131420183. The next prime is 2111131420259. The reversal of 2111131420253 is 3520241311112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1756531416964 + 354600003289 = 1325342^2 + 595483^2 .

It is a cyclic number.

It is not a de Polignac number, because 2111131420253 - 2²⁴ = 2111114643037 is a prime.

It is a super-3 number, since 3×2111131420253³ (a number of 38 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2111131420259) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055565710126 + 1055565710127.

It is an arithmetic number, because the mean of its divisors is an integer number (1055565710127).

Almost surely, 2^{2111131420253} is an apocalyptic number.

It is an amenable number.

2111131420253 is a deficient number, since it is larger than the sum of its proper divisors (1).

2111131420253 is an equidigital number, since it uses as much as digits as its factorization.

2111131420253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 2111131420253 its reverse (3520241311112), we get a palindrome (5631372731365).

The spelling of 2111131420253 in words is "two trillion, one hundred eleven billion, one hundred thirty-one million, four hundred twenty thousand, two hundred fifty-three".