Base | Representation |
---|---|
bin | 110000000000000110101101… |
… | …000000101110111111001111 |
3 | 1000200111020122221010102222221 |
4 | 300000012231000232333033 |
5 | 210132340301104313434 |
6 | 2025000100530520211 |
7 | 62316304414054156 |
oct | 6000065500567717 |
9 | 1020436587112887 |
10 | 211113430151119 |
11 | 612a3780671701 |
12 | 1b817244736067 |
13 | 90a4bac731642 |
14 | 3a1bd31b5859d |
15 | 1961828a522b4 |
hex | c001ad02efcf |
211113430151119 has 4 divisors (see below), whose sum is σ = 211113713325744. Its totient is φ = 211113146976496.
The previous prime is 211113430151101. The next prime is 211113430151167. The reversal of 211113430151119 is 911151034311112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 211113430151119 - 215 = 211113430118351 is a prime.
It is a super-2 number, since 2×2111134301511192 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211113430151219) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 140466067 + ... + 141961060.
It is an arithmetic number, because the mean of its divisors is an integer number (52778428331436).
Almost surely, 2211113430151119 is an apocalyptic number.
211113430151119 is a deficient number, since it is larger than the sum of its proper divisors (283174625).
211113430151119 is an equidigital number, since it uses as much as digits as its factorization.
211113430151119 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 283174624.
The product of its (nonzero) digits is 3240, while the sum is 34.
The spelling of 211113430151119 in words is "two hundred eleven trillion, one hundred thirteen billion, four hundred thirty million, one hundred fifty-one thousand, one hundred nineteen".
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