Base | Representation |
---|---|
bin | 11110101110001101011… |
… | …001011111011011011001 |
3 | 21110211101020112201120222 |
4 | 132232031121133123121 |
5 | 234042220002241441 |
6 | 4253512240525425 |
7 | 305346351132461 |
oct | 36561531373331 |
9 | 7424336481528 |
10 | 2111201212121 |
11 | 7443a0055391 |
12 | 2a11b9020875 |
13 | 12411588b381 |
14 | 7427b3daba1 |
15 | 39db579ed4b |
hex | 1eb8d65f6d9 |
2111201212121 has 4 divisors (see below), whose sum is σ = 2111214015744. Its totient is φ = 2111188408500.
The previous prime is 2111201212093. The next prime is 2111201212123. The reversal of 2111201212121 is 1212121021112.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2111201212121 - 214 = 2111201195737 is a prime.
It is a super-2 number, since 2×21112012121212 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 2111201212121.
It is not an unprimeable number, because it can be changed into a prime (2111201212123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6151205 + ... + 6485346.
It is an arithmetic number, because the mean of its divisors is an integer number (527803503936).
Almost surely, 22111201212121 is an apocalyptic number.
It is an amenable number.
2111201212121 is a deficient number, since it is larger than the sum of its proper divisors (12803623).
2111201212121 is a wasteful number, since it uses less digits than its factorization.
2111201212121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12803622.
The product of its (nonzero) digits is 32, while the sum is 17.
Adding to 2111201212121 its reverse (1212121021112), we get a palindrome (3323322233233).
It can be divided in two parts, 211120 and 1212121, that added together give a palindrome (1423241).
The spelling of 2111201212121 in words is "two trillion, one hundred eleven billion, two hundred one million, two hundred twelve thousand, one hundred twenty-one".
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