Base | Representation |
---|---|
bin | 110000000000001101000000… |
… | …100001101010001010000011 |
3 | 1000200111220010201210101222112 |
4 | 300000031000201222022003 |
5 | 210132443132200001011 |
6 | 2025003140404125535 |
7 | 62316634236611252 |
oct | 6000150041521203 |
9 | 1020456121711875 |
10 | 211120200000131 |
11 | 612a663500a444 |
12 | 1b8186139968ab |
13 | 90a571b154666 |
14 | 3a1c3b4cc4799 |
15 | 1961ac305858b |
hex | c0034086a283 |
211120200000131 has 2 divisors, whose sum is σ = 211120200000132. Its totient is φ = 211120200000130.
The previous prime is 211120200000109. The next prime is 211120200000179. The reversal of 211120200000131 is 131000002021112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211120200000131 - 230 = 211119126258307 is a prime.
It is a super-2 number, since 2×2111202000001312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (211120200020131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105560100000065 + 105560100000066.
It is an arithmetic number, because the mean of its divisors is an integer number (105560100000066).
Almost surely, 2211120200000131 is an apocalyptic number.
211120200000131 is a deficient number, since it is larger than the sum of its proper divisors (1).
211120200000131 is an equidigital number, since it uses as much as digits as its factorization.
211120200000131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 211120200000131 its reverse (131000002021112), we get a palindrome (342120202021243).
The spelling of 211120200000131 in words is "two hundred eleven trillion, one hundred twenty billion, two hundred million, one hundred thirty-one", and thus it is an aban number.
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