Base | Representation |
---|---|
bin | 11110101110001101100… |
… | …101110011110101101101 |
3 | 21110211101110121210101212 |
4 | 132232031211303311231 |
5 | 234042221314111303 |
6 | 4253512434044205 |
7 | 305346420442442 |
oct | 36561545636555 |
9 | 7424343553355 |
10 | 2111204441453 |
11 | 7443a1960658 |
12 | 2a11ba119665 |
13 | 12411644c213 |
14 | 7427b9db9c9 |
15 | 39db5bdbad8 |
hex | 1eb8d973d6d |
2111204441453 has 2 divisors, whose sum is σ = 2111204441454. Its totient is φ = 2111204441452.
The previous prime is 2111204441441. The next prime is 2111204441473. The reversal of 2111204441453 is 3541444021112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1826222498884 + 284981942569 = 1351378^2 + 533837^2 .
It is a cyclic number.
It is not a de Polignac number, because 2111204441453 - 218 = 2111204179309 is a prime.
It is a super-2 number, since 2×21112044414532 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2111204441473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055602220726 + 1055602220727.
It is an arithmetic number, because the mean of its divisors is an integer number (1055602220727).
Almost surely, 22111204441453 is an apocalyptic number.
It is an amenable number.
2111204441453 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111204441453 is an equidigital number, since it uses as much as digits as its factorization.
2111204441453 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15360, while the sum is 32.
Adding to 2111204441453 its reverse (3541444021112), we get a palindrome (5652648462565).
The spelling of 2111204441453 in words is "two trillion, one hundred eleven billion, two hundred four million, four hundred forty-one thousand, four hundred fifty-three".
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