Base | Representation |
---|---|
bin | 1100010010011111001… |
… | …1001000001111010001 |
3 | 202011221101121201012002 |
4 | 3010213303020033101 |
5 | 11424334001041032 |
6 | 240553202043345 |
7 | 21152530562054 |
oct | 3044763101721 |
9 | 664841551162 |
10 | 211121112017 |
11 | 81599400272 |
12 | 34b00049555 |
13 | 16ba736c92a |
14 | a30b0baa9b |
15 | 5759988862 |
hex | 3127cc83d1 |
211121112017 has 2 divisors, whose sum is σ = 211121112018. Its totient is φ = 211121112016.
The previous prime is 211121112001. The next prime is 211121112049. The reversal of 211121112017 is 710211121112.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 114747497536 + 96373614481 = 338744^2 + 310441^2 .
It is a cyclic number.
It is not a de Polignac number, because 211121112017 - 24 = 211121112001 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 211121112017.
It is not a weakly prime, because it can be changed into another prime (211121112217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105560556008 + 105560556009.
It is an arithmetic number, because the mean of its divisors is an integer number (105560556009).
Almost surely, 2211121112017 is an apocalyptic number.
It is an amenable number.
211121112017 is a deficient number, since it is larger than the sum of its proper divisors (1).
211121112017 is an equidigital number, since it uses as much as digits as its factorization.
211121112017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 20.
Adding to 211121112017 its reverse (710211121112), we get a palindrome (921332233129).
The spelling of 211121112017 in words is "two hundred eleven billion, one hundred twenty-one million, one hundred twelve thousand, seventeen".
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