211121114081 has 2 divisors, whose sum is σ = 211121114082. Its totient is φ = 211121114080.

The previous prime is 211121114069. The next prime is 211121114137. The reversal of 211121114081 is 180411121112.

211121114081 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 186351075856 + 24770038225 = 431684^2 + 157385^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-211121114081 is a prime.

It is a super-2 number, since 2×211121114081² (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (211121114011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105560557040 + 105560557041.

It is an arithmetic number, because the mean of its divisors is an integer number (105560557041).

Almost surely, 2^211121114081 is an apocalyptic number.

It is an amenable number.

211121114081 is a deficient number, since it is larger than the sum of its proper divisors (1).

211121114081 is an equidigital number, since it uses as much as digits as its factorization.

211121114081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 128, while the sum is 23.

Adding to 211121114081 its reverse (180411121112), we get a palindrome (391532235193).

The spelling of 211121114081 in words is "two hundred eleven billion, one hundred twenty-one million, one hundred fourteen thousand, eighty-one".