Base | Representation |
---|---|
bin | 1001100110011100011001… |
… | …00010100001111110010011 |
3 | 2202202022002002102212210211 |
4 | 10303032030202201332103 |
5 | 10231400111230402011 |
6 | 112522435222504551 |
7 | 4306205032053235 |
oct | 463161442417623 |
9 | 82668062385724 |
10 | 21112122122131 |
11 | 67aa667600887 |
12 | 244b806b95157 |
13 | ba1b31611631 |
14 | 52db91652255 |
15 | 269294b7bb21 |
hex | 13338c8a1f93 |
21112122122131 has 2 divisors, whose sum is σ = 21112122122132. Its totient is φ = 21112122122130.
The previous prime is 21112122122051. The next prime is 21112122122153. The reversal of 21112122122131 is 13122122121112.
It is an a-pointer prime, because the next prime (21112122122153) can be obtained adding 21112122122131 to its sum of digits (22).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21112122122131 - 213 = 21112122113939 is a prime.
It is a super-2 number, since 2×211121221221312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21112122125131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10556061061065 + 10556061061066.
It is an arithmetic number, because the mean of its divisors is an integer number (10556061061066).
Almost surely, 221112122122131 is an apocalyptic number.
21112122122131 is a deficient number, since it is larger than the sum of its proper divisors (1).
21112122122131 is an equidigital number, since it uses as much as digits as its factorization.
21112122122131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 192, while the sum is 22.
Adding to 21112122122131 its reverse (13122122121112), we get a palindrome (34234244243243).
The spelling of 21112122122131 in words is "twenty-one trillion, one hundred twelve billion, one hundred twenty-two million, one hundred twenty-two thousand, one hundred thirty-one".
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