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211122012001 = 1581431335007
BaseRepresentation
bin1100010010011111011…
…0100011111101100001
3202011221110022102201211
43010213312203331201
511424334213341001
6240553233230121
721152541330655
oct3044766437541
9664843272654
10211122012001
118159996545a
1234b00402341
1316ba75c6474
14a30b272a65
155759ab5351
hex3127da3f61

211122012001 has 4 divisors (see below), whose sum is σ = 211123505152. Its totient is φ = 211120518852.

The previous prime is 211122011963. The next prime is 211122012007. The reversal of 211122012001 is 100210221112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 211122012001 - 29 = 211122011489 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (211122012007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 509361 + ... + 825646.

It is an arithmetic number, because the mean of its divisors is an integer number (52780876288).

Almost surely, 2211122012001 is an apocalyptic number.

It is an amenable number.

211122012001 is a deficient number, since it is larger than the sum of its proper divisors (1493151).

211122012001 is a wasteful number, since it uses less digits than its factorization.

211122012001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1493150.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 211122012001 its reverse (100210221112), we get a palindrome (311332233113).

The spelling of 211122012001 in words is "two hundred eleven billion, one hundred twenty-two million, twelve thousand, one".

Divisors: 1 158143 1335007 211122012001