Base | Representation |
---|---|
bin | 110000000000001110101101… |
… | …001000000101010100101111 |
3 | 1000200112001211201020012200021 |
4 | 300000032231020011110233 |
5 | 210133010400113342312 |
6 | 2025004041252143011 |
7 | 62320030342504645 |
oct | 6000165510052457 |
9 | 1020461751205607 |
10 | 211122022012207 |
11 | 612a738a539049 |
12 | 1b818a42007a67 |
13 | 90a594b780907 |
14 | 3a1c508c8b195 |
15 | 1961b7ceadc07 |
hex | c003ad20552f |
211122022012207 has 2 divisors, whose sum is σ = 211122022012208. Its totient is φ = 211122022012206.
The previous prime is 211122022012171. The next prime is 211122022012249. The reversal of 211122022012207 is 702210220221112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211122022012207 - 231 = 211119874528559 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211122022072207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105561011006103 + 105561011006104.
It is an arithmetic number, because the mean of its divisors is an integer number (105561011006104).
Almost surely, 2211122022012207 is an apocalyptic number.
211122022012207 is a deficient number, since it is larger than the sum of its proper divisors (1).
211122022012207 is an equidigital number, since it uses as much as digits as its factorization.
211122022012207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 896, while the sum is 25.
Adding to 211122022012207 its reverse (702210220221112), we get a palindrome (913332242233319).
The spelling of 211122022012207 in words is "two hundred eleven trillion, one hundred twenty-two billion, twenty-two million, twelve thousand, two hundred seven".
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