21112300113 has 4 divisors (see below), whose sum is σ = 28149733488. Its totient is φ = 14074866740.

The previous prime is 21112300087. The next prime is 21112300123. The reversal of 21112300113 is 31100321112.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21112300113 - 2⁵ = 21112300081 is a prime.

It is a super-2 number, since 2×21112300113² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21112300092 and 21112300101.

It is not an unprimeable number, because it can be changed into a prime (21112300123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3518716683 + ... + 3518716688.

It is an arithmetic number, because the mean of its divisors is an integer number (7037433372).

Almost surely, 2^21112300113 is an apocalyptic number.

It is an amenable number.

21112300113 is a deficient number, since it is larger than the sum of its proper divisors (7037433375).

21112300113 is an equidigital number, since it uses as much as digits as its factorization.

21112300113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7037433374.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 21112300113 its reverse (31100321112), we get a palindrome (52212621225).

The spelling of 21112300113 in words is "twenty-one billion, one hundred twelve million, three hundred thousand, one hundred thirteen".