Base | Representation |
---|---|
bin | 110000000000001111101001… |
… | …110011111010010010111010 |
3 | 1000200112011110200000011200001 |
4 | 300000033221303322102322 |
5 | 210133014441233244310 |
6 | 2025004330302103214 |
7 | 62320064514424012 |
oct | 6000175163722272 |
9 | 1020464420004601 |
10 | 211123040134330 |
11 | 612a786220a295 |
12 | 1b819086b7ab0a |
13 | 90a5a8169453c |
14 | 3a1c5a4194c42 |
15 | 1961bdc56e93a |
hex | c003e9cfa4ba |
211123040134330 has 32 divisors (see below), whose sum is σ = 384938460057600. Its totient is φ = 83363235056640.
The previous prime is 211123040134327. The next prime is 211123040134333. The reversal of 211123040134330 is 33431040321112.
It is an interprime number because it is at equal distance from previous prime (211123040134327) and next prime (211123040134333).
It is not an unprimeable number, because it can be changed into a prime (211123040134333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 417432231 + ... + 417937690.
It is an arithmetic number, because the mean of its divisors is an integer number (12029326876800).
Almost surely, 2211123040134330 is an apocalyptic number.
211123040134330 is a deficient number, since it is larger than the sum of its proper divisors (173815419923270).
211123040134330 is a wasteful number, since it uses less digits than its factorization.
211123040134330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 835370254.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 211123040134330 its reverse (33431040321112), we get a palindrome (244554080455442).
The spelling of 211123040134330 in words is "two hundred eleven trillion, one hundred twenty-three billion, forty million, one hundred thirty-four thousand, three hundred thirty".
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