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2111254036013 = 13116116443023
BaseRepresentation
bin11110101110010000100…
…010111111111000101101
321110211111220221110100102
4132232100202333320231
5234042322013123023
64253521405040445
7305350562131133
oct36562042777055
97424456843312
102111254036013
117444179547a1
122a1212856125
131241237c4c05
147428442b753
1539dba236628
hex1eb908bfe2d

2111254036013 has 4 divisors (see below), whose sum is σ = 2127370479168. Its totient is φ = 2095137592860.

The previous prime is 2111254036009. The next prime is 2111254036049. The reversal of 2111254036013 is 3106304521112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2111254036013 - 22 = 2111254036009 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2111254038013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8058221381 + ... + 8058221642.

It is an arithmetic number, because the mean of its divisors is an integer number (531842619792).

Almost surely, 22111254036013 is an apocalyptic number.

It is an amenable number.

2111254036013 is a deficient number, since it is larger than the sum of its proper divisors (16116443155).

2111254036013 is a wasteful number, since it uses less digits than its factorization.

2111254036013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16116443154.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 2111254036013 its reverse (3106304521112), we get a palindrome (5217558557125).

The spelling of 2111254036013 in words is "two trillion, one hundred eleven billion, two hundred fifty-four million, thirty-six thousand, thirteen".

Divisors: 1 131 16116443023 2111254036013