211130000113 has 4 divisors (see below), whose sum is σ = 213802531840. Its totient is φ = 208457468388.

The previous prime is 211130000069. The next prime is 211130000131. The reversal of 211130000113 is 311000031112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 211130000113 - 2⁹ = 211129999601 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 211130000093 and 211130000102.

It is not an unprimeable number, because it can be changed into a prime (211130000173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1336265745 + ... + 1336265902.

It is an arithmetic number, because the mean of its divisors is an integer number (53450632960).

Almost surely, 2^211130000113 is an apocalyptic number.

It is an amenable number.

211130000113 is a deficient number, since it is larger than the sum of its proper divisors (2672531727).

211130000113 is an equidigital number, since it uses as much as digits as its factorization.

211130000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2672531726.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 211130000113 its reverse (311000031112), we get a palindrome (522130031225).

The spelling of 211130000113 in words is "two hundred eleven billion, one hundred thirty million, one hundred thirteen", and thus it is an aban number.