2111300044111 has 4 divisors (see below), whose sum is σ = 2111559202872. Its totient is φ = 2111040885352.

The previous prime is 2111300044067. The next prime is 2111300044153. The reversal of 2111300044111 is 1114400031112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2111300044111 - 2¹³ = 2111300035919 is a prime.

It is a super-2 number, since 2×2111300044111² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2111300074111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 129567160 + ... + 129583453.

It is an arithmetic number, because the mean of its divisors is an integer number (527889800718).

Almost surely, 2^{2111300044111} is an apocalyptic number.

2111300044111 is a deficient number, since it is larger than the sum of its proper divisors (259158761).

2111300044111 is an equidigital number, since it uses as much as digits as its factorization.

2111300044111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 259158760.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 2111300044111 its reverse (1114400031112), we get a palindrome (3225700075223).

The spelling of 2111300044111 in words is "two trillion, one hundred eleven billion, three hundred million, forty-four thousand, one hundred eleven".