Search a number
-
+
2111300101 = 3803555167
BaseRepresentation
bin111110111010111…
…1110001000000101
312110010210011021001
41331311332020011
513310443100401
6545300253301
7103214516611
oct17565761005
95403704231
102111300101
11993857019
124ab0a1231
13278546401
1416058c341
15c554a601
hex7dd7e205

2111300101 has 4 divisors (see below), whose sum is σ = 2111859072. Its totient is φ = 2110741132.

The previous prime is 2111300089. The next prime is 2111300143. The reversal of 2111300101 is 1010031112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2111300101 - 25 = 2111300069 is a prime.

It is a super-2 number, since 2×21113001012 = 8915176232965220402, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2111300171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 273781 + ... + 281386.

It is an arithmetic number, because the mean of its divisors is an integer number (527964768).

Almost surely, 22111300101 is an apocalyptic number.

It is an amenable number.

2111300101 is a deficient number, since it is larger than the sum of its proper divisors (558971).

2111300101 is an equidigital number, since it uses as much as digits as its factorization.

2111300101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 558970.

The product of its (nonzero) digits is 6, while the sum is 10.

The square root of 2111300101 is about 45948.8857427468. The cubic root of 2111300101 is about 1282.8719896939.

Adding to 2111300101 its reverse (1010031112), we get a palindrome (3121331213).

The spelling of 2111300101 in words is "two billion, one hundred eleven million, three hundred thousand, one hundred one".

Divisors: 1 3803 555167 2111300101