2111300299969 has 4 divisors (see below), whose sum is σ = 2412914628544. Its totient is φ = 1809685971396.

The previous prime is 2111300299931. The next prime is 2111300300077. The reversal of 2111300299969 is 9699920031112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2111300299969 - 2¹³ = 2111300291777 is a prime.

It is a super-2 number, since 2×2111300299969² (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (2111300299169) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 150807164277 + ... + 150807164290.

It is an arithmetic number, because the mean of its divisors is an integer number (603228657136).

Almost surely, 2^{2111300299969} is an apocalyptic number.

It is an amenable number.

2111300299969 is a deficient number, since it is larger than the sum of its proper divisors (301614328575).

2111300299969 is an equidigital number, since it uses as much as digits as its factorization.

2111300299969 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 301614328574.

The product of its (nonzero) digits is 472392, while the sum is 52.

The spelling of 2111300299969 in words is "two trillion, one hundred eleven billion, three hundred million, two hundred ninety-nine thousand, nine hundred sixty-nine".