211130044403 has 4 divisors (see below), whose sum is σ = 212190999600. Its totient is φ = 210069089208.

The previous prime is 211130044399. The next prime is 211130044453. The reversal of 211130044403 is 304440031112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 211130044403 - 2² = 211130044399 is a prime.

It is a super-2 number, since 2×211130044403² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (211130044453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 530477300 + ... + 530477697.

It is an arithmetic number, because the mean of its divisors is an integer number (53047749900).

Almost surely, 2^211130044403 is an apocalyptic number.

211130044403 is a deficient number, since it is larger than the sum of its proper divisors (1060955197).

211130044403 is a wasteful number, since it uses less digits than its factorization.

211130044403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1060955196.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 211130044403 its reverse (304440031112), we get a palindrome (515570075515).

The spelling of 211130044403 in words is "two hundred eleven billion, one hundred thirty million, forty-four thousand, four hundred three".