Base | Representation |
---|---|
bin | 1001100110011110000011… |
… | …00001111000100111000011 |
3 | 2202202101101001021221010111 |
4 | 10303033001201320213003 |
5 | 10231403421323121110 |
6 | 112523103341412151 |
7 | 4306236045453136 |
oct | 463170141704703 |
9 | 82671331257114 |
10 | 21113011145155 |
11 | 67aaa83415a56 |
12 | 244ba1486a057 |
13 | ba1c43863867 |
14 | 52dc3775221d |
15 | 2692e7c3ae8a |
hex | 1333c18789c3 |
21113011145155 has 8 divisors (see below), whose sum is σ = 25341743477232. Its totient is φ = 16886322180768.
The previous prime is 21113011145143. The next prime is 21113011145167. The reversal of 21113011145155 is 55154111031112.
It is an interprime number because it is at equal distance from previous prime (21113011145143) and next prime (21113011145167).
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 21113011145155 - 217 = 21113011014083 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 510819189 + ... + 510860518.
It is an arithmetic number, because the mean of its divisors is an integer number (3167717934654).
Almost surely, 221113011145155 is an apocalyptic number.
21113011145155 is a deficient number, since it is larger than the sum of its proper divisors (4228732332077).
21113011145155 is a wasteful number, since it uses less digits than its factorization.
21113011145155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1021683845.
The product of its (nonzero) digits is 3000, while the sum is 31.
Adding to 21113011145155 its reverse (55154111031112), we get a palindrome (76267122176267).
The spelling of 21113011145155 in words is "twenty-one trillion, one hundred thirteen billion, eleven million, one hundred forty-five thousand, one hundred fifty-five".
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