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21113011145155 = 541331021679707
BaseRepresentation
bin1001100110011110000011…
…00001111000100111000011
32202202101101001021221010111
410303033001201320213003
510231403421323121110
6112523103341412151
74306236045453136
oct463170141704703
982671331257114
1021113011145155
1167aaa83415a56
12244ba1486a057
13ba1c43863867
1452dc3775221d
152692e7c3ae8a
hex1333c18789c3

21113011145155 has 8 divisors (see below), whose sum is σ = 25341743477232. Its totient is φ = 16886322180768.

The previous prime is 21113011145143. The next prime is 21113011145167. The reversal of 21113011145155 is 55154111031112.

It is an interprime number because it is at equal distance from previous prime (21113011145143) and next prime (21113011145167).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 21113011145155 - 217 = 21113011014083 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 510819189 + ... + 510860518.

It is an arithmetic number, because the mean of its divisors is an integer number (3167717934654).

Almost surely, 221113011145155 is an apocalyptic number.

21113011145155 is a deficient number, since it is larger than the sum of its proper divisors (4228732332077).

21113011145155 is a wasteful number, since it uses less digits than its factorization.

21113011145155 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1021683845.

The product of its (nonzero) digits is 3000, while the sum is 31.

Adding to 21113011145155 its reverse (55154111031112), we get a palindrome (76267122176267).

The spelling of 21113011145155 in words is "twenty-one trillion, one hundred thirteen billion, eleven million, one hundred forty-five thousand, one hundred fifty-five".

Divisors: 1 5 4133 20665 1021679707 5108398535 4222602229031 21113011145155