Base | Representation |
---|---|
bin | 1100010010100001010… |
… | …1110101111111101011 |
3 | 202011222000202001110202 |
4 | 3010220111311333223 |
5 | 11424343313243311 |
6 | 240554125102415 |
7 | 21153001123433 |
oct | 3045025657753 |
9 | 664860661422 |
10 | 211130212331 |
11 | 815a3556495 |
12 | 34b030b7a0b |
13 | 16ba9207b2c |
14 | a30c3a92c3 |
15 | 575a684e3b |
hex | 3128575feb |
211130212331 has 2 divisors, whose sum is σ = 211130212332. Its totient is φ = 211130212330.
The previous prime is 211130212313. The next prime is 211130212339. The reversal of 211130212331 is 133212031112.
It is a happy number.
Together with previous prime (211130212313) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211130212331 is a prime.
It is a super-2 number, since 2×2111302123312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (211130212339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105565106165 + 105565106166.
It is an arithmetic number, because the mean of its divisors is an integer number (105565106166).
Almost surely, 2211130212331 is an apocalyptic number.
211130212331 is a deficient number, since it is larger than the sum of its proper divisors (1).
211130212331 is an equidigital number, since it uses as much as digits as its factorization.
211130212331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 211130212331 its reverse (133212031112), we get a palindrome (344342243443).
The spelling of 211130212331 in words is "two hundred eleven billion, one hundred thirty million, two hundred twelve thousand, three hundred thirty-one".
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