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21113031421414 = 210556515710707
BaseRepresentation
bin1001100110011110000101…
…01111001110110111100110
32202202101102110110001221001
410303033002233032313212
510231403442020441124
6112523105344143514
74306236413012452
oct463170257166746
982671373401831
1021113031421414
1167aaa93904899
12244ba1b607b9a
13ba1c47b1294a
1452dc3a30d662
152692e98e3b44
hex1333c2bcede6

21113031421414 has 4 divisors (see below), whose sum is σ = 31669547132124. Its totient is φ = 10556515710706.

The previous prime is 21113031421403. The next prime is 21113031421421. The reversal of 21113031421414 is 41412413031112.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×211130314214142 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5278257855352 + ... + 5278257855355.

It is an arithmetic number, because the mean of its divisors is an integer number (7917386783031).

Almost surely, 221113031421414 is an apocalyptic number.

21113031421414 is a deficient number, since it is larger than the sum of its proper divisors (10556515710710).

21113031421414 is a wasteful number, since it uses less digits than its factorization.

21113031421414 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10556515710709.

The product of its (nonzero) digits is 2304, while the sum is 28.

Adding to 21113031421414 its reverse (41412413031112), we get a palindrome (62525444452526).

The spelling of 21113031421414 in words is "twenty-one trillion, one hundred thirteen billion, thirty-one million, four hundred twenty-one thousand, four hundred fourteen".

Divisors: 1 2 10556515710707 21113031421414