Base | Representation |
---|---|
bin | 1100010010100001011… |
… | …0010110001001111111 |
3 | 202011222000222202011201 |
4 | 3010220112112021333 |
5 | 11424343332002223 |
6 | 240554132000331 |
7 | 21153002212462 |
oct | 3045026261177 |
9 | 664860882151 |
10 | 211130344063 |
11 | 815a3636461 |
12 | 34b031600a7 |
13 | 16ba9252a92 |
14 | a30c4012d9 |
15 | 575a6adead |
hex | 312859627f |
211130344063 has 2 divisors, whose sum is σ = 211130344064. Its totient is φ = 211130344062.
The previous prime is 211130344057. The next prime is 211130344109. The reversal of 211130344063 is 360443031112.
211130344063 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211130344063 - 25 = 211130344031 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211133344063) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105565172031 + 105565172032.
It is an arithmetic number, because the mean of its divisors is an integer number (105565172032).
Almost surely, 2211130344063 is an apocalyptic number.
211130344063 is a deficient number, since it is larger than the sum of its proper divisors (1).
211130344063 is an equidigital number, since it uses as much as digits as its factorization.
211130344063 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 211130344063 its reverse (360443031112), we get a palindrome (571573375175).
The spelling of 211130344063 in words is "two hundred eleven billion, one hundred thirty million, three hundred forty-four thousand, sixty-three".
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