2111304031113 has 8 divisors (see below), whose sum is σ = 2818604130048. Its totient is φ = 1405769976464.

The previous prime is 2111304031093. The next prime is 2111304031127. The reversal of 2111304031113 is 3111304031112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2111304031113 - 2⁹ = 2111304030601 is a prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 2111304031113.

It is not an unprimeable number, because it can be changed into a prime (2111304031163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 441508281 + ... + 441513062.

It is an arithmetic number, because the mean of its divisors is an integer number (352325516256).

Almost surely, 2^{2111304031113} is an apocalyptic number.

It is an amenable number.

2111304031113 is a deficient number, since it is larger than the sum of its proper divisors (707300098935).

2111304031113 is an equidigital number, since it uses as much as digits as its factorization.

2111304031113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 883022143.

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 2111304031113 its reverse (3111304031112), we get a palindrome (5222608062225).

Subtracting 2111304031113 from its reverse (3111304031112), we obtain a palindrome (999999999999).

The spelling of 2111304031113 in words is "two trillion, one hundred eleven billion, three hundred four million, thirty-one thousand, one hundred thirteen".