Base | Representation |
---|---|
bin | 1001100110011110001110… |
… | …11011011010010001000111 |
3 | 2202202101121221111221011101 |
4 | 10303033013123122101013 |
5 | 10231404122142030203 |
6 | 112523121234520531 |
7 | 4306241356611160 |
oct | 463170733322107 |
9 | 82671557457141 |
10 | 21113110111303 |
11 | 6800024270761 |
12 | 244ba41a36147 |
13 | ba1c5b204902 |
14 | 52dc46954767 |
15 | 26930178941d |
hex | 1333c76da447 |
21113110111303 has 8 divisors (see below), whose sum is σ = 24129316190880. Its totient is φ = 18096915904800.
The previous prime is 21113110111283. The next prime is 21113110111307. The reversal of 21113110111303 is 30311101131112.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 21113110111303 - 29 = 21113110110791 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21113110111307) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1239993 + ... + 6615421.
It is an arithmetic number, because the mean of its divisors is an integer number (3016164523860).
Almost surely, 221113110111303 is an apocalyptic number.
21113110111303 is a deficient number, since it is larger than the sum of its proper divisors (3016206079577).
21113110111303 is an equidigital number, since it uses as much as digits as its factorization.
21113110111303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5936537.
The product of its (nonzero) digits is 54, while the sum is 19.
Adding to 21113110111303 its reverse (30311101131112), we get a palindrome (51424211242415).
The spelling of 21113110111303 in words is "twenty-one trillion, one hundred thirteen billion, one hundred ten million, one hundred eleven thousand, three hundred three".
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