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211131121200133 is a prime number
BaseRepresentation
bin110000000000010111001011…
…011110101110110000000101
31000200112221022211221211221111
4300000113023132232300011
5210133133014011401013
62025012144215245021
762320502001356431
oct6000271336566005
91020487284854844
10211131121200133
1161300229816672
121b81a761379771
1390a676b94bb94
143a1cb2d5219c1
151962011c2e73d
hexc005cb7aec05

211131121200133 has 2 divisors, whose sum is σ = 211131121200134. Its totient is φ = 211131121200132.

The previous prime is 211131121200121. The next prime is 211131121200149. The reversal of 211131121200133 is 331002121131112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 201925862043844 + 9205259156289 = 14210062^2 + 3034017^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211131121200133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211131121270133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105565560600066 + 105565560600067.

It is an arithmetic number, because the mean of its divisors is an integer number (105565560600067).

Almost surely, 2211131121200133 is an apocalyptic number.

It is an amenable number.

211131121200133 is a deficient number, since it is larger than the sum of its proper divisors (1).

211131121200133 is an equidigital number, since it uses as much as digits as its factorization.

211131121200133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 22.

Adding to 211131121200133 its reverse (331002121131112), we get a palindrome (542133242331245).

The spelling of 211131121200133 in words is "two hundred eleven trillion, one hundred thirty-one billion, one hundred twenty-one million, two hundred thousand, one hundred thirty-three".