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211131130331 = 11611013115361
BaseRepresentation
bin1100010010100001100…
…1010110000111011011
3202011222002110200201202
43010220121112013123
511424344032132311
6240554200504415
721153011666012
oct3045031260733
9664862420652
10211131130331
11815a4023170
1234b0347b10b
1316ba9469924
14a30c567a79
15575a7b6e3b
hex31286561db

211131130331 has 16 divisors (see below), whose sum is σ = 236418591456. Its totient is φ = 186921600000.

The previous prime is 211131130321. The next prime is 211131130333. The reversal of 211131130331 is 133031131112.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211131130331 is a prime.

It is a super-3 number, since 3×2111311303313 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (211131130333) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1489910 + ... + 1625451.

It is an arithmetic number, because the mean of its divisors is an integer number (14776161966).

Almost surely, 2211131130331 is an apocalyptic number.

211131130331 is a deficient number, since it is larger than the sum of its proper divisors (25287461125).

211131130331 is a wasteful number, since it uses less digits than its factorization.

211131130331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3115534.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 211131130331 its reverse (133031131112), we get a palindrome (344162261443).

The spelling of 211131130331 in words is "two hundred eleven billion, one hundred thirty-one million, one hundred thirty thousand, three hundred thirty-one".

Divisors: 1 11 61 101 671 1111 6161 67771 3115361 34268971 190037021 314651461 2090407231 3461166071 19193739121 211131130331