2111311313 has 2 divisors, whose sum is σ = 2111311314. Its totient is φ = 2111311312.

The previous prime is 2111311271. The next prime is 2111311333. The reversal of 2111311313 is 3131131112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1896776704 + 214534609 = 43552^2 + 14647^2 .

It is a cyclic number.

It is not a de Polignac number, because 2111311313 - 2²⁴ = 2094534097 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2111311291 and 2111311300.

It is not a weakly prime, because it can be changed into another prime (2111311333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055655656 + 1055655657.

It is an arithmetic number, because the mean of its divisors is an integer number (1055655657).

Almost surely, 2^2111311313 is an apocalyptic number.

It is an amenable number.

2111311313 is a deficient number, since it is larger than the sum of its proper divisors (1).

2111311313 is an equidigital number, since it uses as much as digits as its factorization.

2111311313 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 54, while the sum is 17.

The square root of 2111311313 is about 45949.0077477196. The cubic root of 2111311313 is about 1282.8742605752.

Adding to 2111311313 its reverse (3131131112), we get a palindrome (5242442425).

The spelling of 2111311313 in words is "two billion, one hundred eleven million, three hundred eleven thousand, three hundred thirteen".