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211131133003 = 730161590429
BaseRepresentation
bin1100010010100001100…
…1010110110001001011
3202011222002110211101201
43010220121112301023
511424344032224003
6240554200525031
721153012006550
oct3045031266113
9664862424351
10211131133003
11815a402517a
1234b03480777
1316ba946abcb
14a30c568a27
15575a7b7b1d
hex3128656c4b

211131133003 has 4 divisors (see below), whose sum is σ = 241292723440. Its totient is φ = 180969542568.

The previous prime is 211131133001. The next prime is 211131133027. The reversal of 211131133003 is 300331131112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 211131133003 - 21 = 211131133001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (211131133001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15080795208 + ... + 15080795221.

It is an arithmetic number, because the mean of its divisors is an integer number (60323180860).

Almost surely, 2211131133003 is an apocalyptic number.

211131133003 is a deficient number, since it is larger than the sum of its proper divisors (30161590437).

211131133003 is an equidigital number, since it uses as much as digits as its factorization.

211131133003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30161590436.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 211131133003 its reverse (300331131112), we get a palindrome (511462264115).

The spelling of 211131133003 in words is "two hundred eleven billion, one hundred thirty-one million, one hundred thirty-three thousand, three".

Divisors: 1 7 30161590429 211131133003