211131234331 has 2 divisors, whose sum is σ = 211131234332. Its totient is φ = 211131234330.

The previous prime is 211131234329. The next prime is 211131234359. The reversal of 211131234331 is 133432131112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 211131234331 - 2¹ = 211131234329 is a prime.

It is a super-2 number, since 2×211131234331² (a number of 23 digits) contains 22 as substring.

Together with 211131234329, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 211131234296 and 211131234305.

It is not a weakly prime, because it can be changed into another prime (211131234131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105565617165 + 105565617166.

It is an arithmetic number, because the mean of its divisors is an integer number (105565617166).

Almost surely, 2^211131234331 is an apocalyptic number.

211131234331 is a deficient number, since it is larger than the sum of its proper divisors (1).

211131234331 is an equidigital number, since it uses as much as digits as its factorization.

211131234331 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1296, while the sum is 25.

Adding to 211131234331 its reverse (133432131112), we get a palindrome (344563365443).

The spelling of 211131234331 in words is "two hundred eleven billion, one hundred thirty-one million, two hundred thirty-four thousand, three hundred thirty-one".