Base | Representation |
---|---|
bin | 1100010010100001100… |
… | …1111011010111111101 |
3 | 202011222002202110001222 |
4 | 3010220121323113331 |
5 | 11424344102023231 |
6 | 240554204043125 |
7 | 21153013202645 |
oct | 3045031732775 |
9 | 664862673058 |
10 | 211131282941 |
11 | 815a4117897 |
12 | 34b035334a5 |
13 | 16ba94c1227 |
14 | a30c5a7525 |
15 | 575a7e727b |
hex | 312867b5fd |
211131282941 has 2 divisors, whose sum is σ = 211131282942. Its totient is φ = 211131282940.
The previous prime is 211131282919. The next prime is 211131282949. The reversal of 211131282941 is 149282131112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 155357375716 + 55773907225 = 394154^2 + 236165^2 .
It is a cyclic number.
It is not a de Polignac number, because 211131282941 - 218 = 211131020797 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211131282949) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105565641470 + 105565641471.
It is an arithmetic number, because the mean of its divisors is an integer number (105565641471).
Almost surely, 2211131282941 is an apocalyptic number.
It is an amenable number.
211131282941 is a deficient number, since it is larger than the sum of its proper divisors (1).
211131282941 is an equidigital number, since it uses as much as digits as its factorization.
211131282941 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6912, while the sum is 35.
The spelling of 211131282941 in words is "two hundred eleven billion, one hundred thirty-one million, two hundred eighty-two thousand, nine hundred forty-one".
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