21113131221331 has 2 divisors, whose sum is σ = 21113131221332. Its totient is φ = 21113131221330.

The previous prime is 21113131221313. The next prime is 21113131221359. The reversal of 21113131221331 is 13312213131112.

Together with previous prime (21113131221313) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 21113131221331 - 2²¹ = 21113129124179 is a prime.

It is a super-2 number, since 2×21113131221331² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21113131221296 and 21113131221305.

It is not a weakly prime, because it can be changed into another prime (21113131221031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10556565610665 + 10556565610666.

It is an arithmetic number, because the mean of its divisors is an integer number (10556565610666).

Almost surely, 2^{21113131221331} is an apocalyptic number.

21113131221331 is a deficient number, since it is larger than the sum of its proper divisors (1).

21113131221331 is an equidigital number, since it uses as much as digits as its factorization.

21113131221331 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 648, while the sum is 25.

Adding to 21113131221331 its reverse (13312213131112), we get a palindrome (34425344352443).

The spelling of 21113131221331 in words is "twenty-one trillion, one hundred thirteen billion, one hundred thirty-one million, two hundred twenty-one thousand, three hundred thirty-one".