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21113133000 = 23353175373107
BaseRepresentation
bin10011101010011100…
…001101011111001000
32000111102002021122220
4103222130031133020
5321214430224000
613411011414040
71345126445421
oct235234153710
960442067586
1021113133000
118a548a4353
1241128b4320
131cb61a620b
141044082648
158388481a0
hex4ea70d7c8

21113133000 has 512 divisors, whose sum is σ = 72710576640. Its totient is φ = 5079859200.

The previous prime is 21113132941. The next prime is 21113133037. The reversal of 21113133000 is 33131112.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 197318947 + ... + 197319053.

It is an arithmetic number, because the mean of its divisors is an integer number (142012845).

Almost surely, 221113133000 is an apocalyptic number.

21113133000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 21113133000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (36355288320).

21113133000 is an abundant number, since it is smaller than the sum of its proper divisors (51597443640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

21113133000 is a wasteful number, since it uses less digits than its factorization.

21113133000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 274 (or 260 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 21113133000 its reverse (33131112), we get a palindrome (21146264112).

The spelling of 21113133000 in words is "twenty-one billion, one hundred thirteen million, one hundred thirty-three thousand".