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211131414061 is a prime number
BaseRepresentation
bin1100010010100001101…
…0011011011000101101
3202011222010000002221021
43010220122123120231
511424344120222221
6240554210534141
721153014260141
oct3045032333055
9664863002837
10211131414061
11815a41a7357
1234b03597351
1316ba9538b09
14a30c5dd221
15575a821041
hex312869b62d

211131414061 has 2 divisors, whose sum is σ = 211131414062. Its totient is φ = 211131414060.

The previous prime is 211131413993. The next prime is 211131414071. The reversal of 211131414061 is 160414131112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 210882089961 + 249324100 = 459219^2 + 15790^2 .

It is a cyclic number.

It is not a de Polignac number, because 211131414061 - 213 = 211131405869 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211131414071) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105565707030 + 105565707031.

It is an arithmetic number, because the mean of its divisors is an integer number (105565707031).

Almost surely, 2211131414061 is an apocalyptic number.

It is an amenable number.

211131414061 is a deficient number, since it is larger than the sum of its proper divisors (1).

211131414061 is an equidigital number, since it uses as much as digits as its factorization.

211131414061 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 211131414061 its reverse (160414131112), we get a palindrome (371545545173).

The spelling of 211131414061 in words is "two hundred eleven billion, one hundred thirty-one million, four hundred fourteen thousand, sixty-one".