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211131430339 is a prime number
BaseRepresentation
bin1100010010100001101…
…0011111010111000011
3202011222010000221021011
43010220122133113003
511424344121232324
6240554211141351
721153014355454
oct3045032372703
9664863027234
10211131430339
11815a4208605
1234b035a4857
1316ba954334b
14a30c60512b
15575a825c94
hex312869f5c3

211131430339 has 2 divisors, whose sum is σ = 211131430340. Its totient is φ = 211131430338.

The previous prime is 211131430337. The next prime is 211131430373. The reversal of 211131430339 is 933034131112.

211131430339 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 211131430339 - 21 = 211131430337 is a prime.

Together with 211131430337, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 211131430339.

It is not a weakly prime, because it can be changed into another prime (211131430337) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105565715169 + 105565715170.

It is an arithmetic number, because the mean of its divisors is an integer number (105565715170).

Almost surely, 2211131430339 is an apocalyptic number.

211131430339 is a deficient number, since it is larger than the sum of its proper divisors (1).

211131430339 is an equidigital number, since it uses as much as digits as its factorization.

211131430339 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5832, while the sum is 31.

The spelling of 211131430339 in words is "two hundred eleven billion, one hundred thirty-one million, four hundred thirty thousand, three hundred thirty-nine".