21113143134300 has 432 divisors, whose sum is σ = 79717560249600. Its totient is φ = 4565841177600.

The previous prime is 21113143134263. The next prime is 21113143134311. The reversal of 21113143134300 is 343134131112.

21113143134300 is a `hidden beast` number, since 2 + 1 + 1 + 1 + 314 + 3 + 1 + 343 + 0 + 0 = 666.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 90975811 + ... + 91207589.

Almost surely, 2^{21113143134300} is an apocalyptic number.

21113143134300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 21113143134300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (39858780124800).

21113143134300 is an abundant number, since it is smaller than the sum of its proper divisors (58604417115300).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

21113143134300 is a wasteful number, since it uses less digits than its factorization.

21113143134300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 232586 (or 232576 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 21113143134300 its reverse (343134131112), we get a palindrome (21456277265412).

The spelling of 21113143134300 in words is "twenty-one trillion, one hundred thirteen billion, one hundred forty-three million, one hundred thirty-four thousand, three hundred".