Base | Representation |
---|---|
bin | 1001100110011110010011… |
… | …00101101010111101011111 |
3 | 2202202101201110201022220221 |
4 | 10303033021211222331133 |
5 | 10231404210431334201 |
6 | 112523125011422211 |
7 | 4306242306644425 |
oct | 463171145527537 |
9 | 82671643638827 |
10 | 21113146355551 |
11 | 6800042776588 |
12 | 244ba51bb4967 |
13 | ba1c65884b03 |
14 | 52dc4b6ab115 |
15 | 269304a484a1 |
hex | 1333c996af5f |
21113146355551 has 4 divisors (see below), whose sum is σ = 21113167549192. Its totient is φ = 21113125161912.
The previous prime is 21113146355513. The next prime is 21113146355627. The reversal of 21113146355551 is 15555364131112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 21113146355551 - 231 = 21110998871903 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 21113146355498 and 21113146355507.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21113146305551) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9024780 + ... + 11120833.
It is an arithmetic number, because the mean of its divisors is an integer number (5278291887298).
Almost surely, 221113146355551 is an apocalyptic number.
21113146355551 is a deficient number, since it is larger than the sum of its proper divisors (21193641).
21113146355551 is a wasteful number, since it uses less digits than its factorization.
21113146355551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21193640.
The product of its digits is 270000, while the sum is 43.
The spelling of 21113146355551 in words is "twenty-one trillion, one hundred thirteen billion, one hundred forty-six million, three hundred fifty-five thousand, five hundred fifty-one".
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