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21113150365631 = 94529223351039
BaseRepresentation
bin1001100110011110010011…
…10100111101111110111111
32202202101201202021001201102
410303033021310331332333
510231404212443200011
6112523125233403315
74306242356015552
oct463171164757677
982671652231642
1021113150365631
116800044a653a5
12244ba5340953b
13ba1c6665a13c
1452dc4c032699
1526930508b73b
hex1333c9d3dfbf

21113150365631 has 4 divisors (see below), whose sum is σ = 21113373811200. Its totient is φ = 21112926920064.

The previous prime is 21113150365519. The next prime is 21113150365673. The reversal of 21113150365631 is 13656305131112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21113150365631 - 226 = 21113083256767 is a prime.

It is a super-2 number, since 2×211131503656312 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21113150365231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111580991 + ... + 111770048.

It is an arithmetic number, because the mean of its divisors is an integer number (5278343452800).

Almost surely, 221113150365631 is an apocalyptic number.

21113150365631 is a deficient number, since it is larger than the sum of its proper divisors (223445569).

21113150365631 is an equidigital number, since it uses as much as digits as its factorization.

21113150365631 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 223445568.

The product of its (nonzero) digits is 48600, while the sum is 38.

Adding to 21113150365631 its reverse (13656305131112), we get a palindrome (34769455496743).

The spelling of 21113150365631 in words is "twenty-one trillion, one hundred thirteen billion, one hundred fifty million, three hundred sixty-five thousand, six hundred thirty-one".

Divisors: 1 94529 223351039 21113150365631