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211132002121 = 401526513721
BaseRepresentation
bin1100010010100001110…
…0101010111101001001
3202011222011002222121021
43010220130222331021
511424344243031441
6240554231312441
721153022256455
oct3045034527511
9664864088537
10211132002121
11815a4569157
1234b0381b721
1316ba96b3691
14a30c713665
15575a8da3d1
hex312872af49

211132002121 has 4 divisors (see below), whose sum is σ = 211658516244. Its totient is φ = 210605488000.

The previous prime is 211132002091. The next prime is 211132002167. The reversal of 211132002121 is 121200231112.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 168809226496 + 42322775625 = 410864^2 + 205725^2 .

It is a cyclic number.

It is not a de Polignac number, because 211132002121 - 235 = 176772263753 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 211132002095 and 211132002104.

It is not an unprimeable number, because it can be changed into a prime (211132002421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 263256460 + ... + 263257261.

It is an arithmetic number, because the mean of its divisors is an integer number (52914629061).

Almost surely, 2211132002121 is an apocalyptic number.

It is an amenable number.

211132002121 is a deficient number, since it is larger than the sum of its proper divisors (526514123).

211132002121 is an equidigital number, since it uses as much as digits as its factorization.

211132002121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 526514122.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 211132002121 its reverse (121200231112), we get a palindrome (332332233233).

The spelling of 211132002121 in words is "two hundred eleven billion, one hundred thirty-two million, two thousand, one hundred twenty-one".

Divisors: 1 401 526513721 211132002121