Base | Representation |
---|---|
bin | 1100010010100001110… |
… | …0101101001000001101 |
3 | 202011222011010102210220 |
4 | 3010220130231020031 |
5 | 11424344243323041 |
6 | 240554231421553 |
7 | 21153022324431 |
oct | 3045034551015 |
9 | 664864112726 |
10 | 211132011021 |
11 | 815a4574908 |
12 | 34b038248b9 |
13 | 16ba96b7749 |
14 | a30c7169c1 |
15 | 575a8dcd66 |
hex | 312872d20d |
211132011021 has 4 divisors (see below), whose sum is σ = 281509348032. Its totient is φ = 140754674012.
The previous prime is 211132011007. The next prime is 211132011073. The reversal of 211132011021 is 120110231112.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 211132011021 - 217 = 211131879949 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211132011121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35188668501 + ... + 35188668506.
It is an arithmetic number, because the mean of its divisors is an integer number (70377337008).
Almost surely, 2211132011021 is an apocalyptic number.
It is an amenable number.
211132011021 is a deficient number, since it is larger than the sum of its proper divisors (70377337011).
211132011021 is an equidigital number, since it uses as much as digits as its factorization.
211132011021 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70377337010.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 211132011021 its reverse (120110231112), we get a palindrome (331242242133).
The spelling of 211132011021 in words is "two hundred eleven billion, one hundred thirty-two million, eleven thousand, twenty-one".
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