Search a number
-
+
211132301230231 is a prime number
BaseRepresentation
bin110000000000011000010001…
…110100001100000010010111
31000200120001101002101120220221
4300000120101310030002113
5210133142423103331411
62025012501251335211
762320543150432423
oct6000302164140227
91020501332346827
10211132301230231
1161300784922757
121b81aa305b1507
1390a68c9270844
143a1cc02133b83
151962080623071
hexc00611d0c097

211132301230231 has 2 divisors, whose sum is σ = 211132301230232. Its totient is φ = 211132301230230.

The previous prime is 211132301230159. The next prime is 211132301230271. The reversal of 211132301230231 is 132032103231112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 211132301230231 - 221 = 211132299133079 is a prime.

It is a super-2 number, since 2×2111323012302312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 211132301230196 and 211132301230205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211132301230271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105566150615115 + 105566150615116.

It is an arithmetic number, because the mean of its divisors is an integer number (105566150615116).

Almost surely, 2211132301230231 is an apocalyptic number.

211132301230231 is a deficient number, since it is larger than the sum of its proper divisors (1).

211132301230231 is an equidigital number, since it uses as much as digits as its factorization.

211132301230231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 211132301230231 its reverse (132032103231112), we get a palindrome (343164404461343).

The spelling of 211132301230231 in words is "two hundred eleven trillion, one hundred thirty-two billion, three hundred one million, two hundred thirty thousand, two hundred thirty-one".