Base | Representation |
---|---|
bin | 11110101110010101001… |
… | …001101111001010011001 |
3 | 21110211201022022212121022 |
4 | 132232111021233022121 |
5 | 234043001303044433 |
6 | 4253533205052225 |
7 | 305352520640426 |
oct | 36562511571231 |
9 | 7424638285538 |
10 | 2111331299993 |
11 | 744457527323 |
12 | 2a12346b7075 |
13 | 124136807b46 |
14 | 742907c0d4d |
15 | 39dc1de9698 |
hex | 1eb9526f299 |
2111331299993 has 2 divisors, whose sum is σ = 2111331299994. Its totient is φ = 2111331299992.
The previous prime is 2111331299951. The next prime is 2111331300017. The reversal of 2111331299993 is 3999921331112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2110197833104 + 1133466889 = 1452652^2 + 33667^2 .
It is a cyclic number.
It is not a de Polignac number, because 2111331299993 - 222 = 2111327105689 is a prime.
It is not a weakly prime, because it can be changed into another prime (2111331299093) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055665649996 + 1055665649997.
It is an arithmetic number, because the mean of its divisors is an integer number (1055665649997).
Almost surely, 22111331299993 is an apocalyptic number.
It is an amenable number.
2111331299993 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111331299993 is an equidigital number, since it uses as much as digits as its factorization.
2111331299993 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 708588, while the sum is 53.
The spelling of 2111331299993 in words is "two trillion, one hundred eleven billion, three hundred thirty-one million, two hundred ninety-nine thousand, nine hundred ninety-three".
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