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2111331300031 is a prime number
BaseRepresentation
bin11110101110010101001…
…001101111001010111111
321110211201022022212122201
4132232111021233022333
5234043001303100111
64253533205052331
7305352520640512
oct36562511571277
97424638285581
102111331300031
11744457527358
122a12346b70a7
13124136807b75
14742907c0d79
1539dc1de96c1
hex1eb9526f2bf

2111331300031 has 2 divisors, whose sum is σ = 2111331300032. Its totient is φ = 2111331300030.

The previous prime is 2111331300017. The next prime is 2111331300037. The reversal of 2111331300031 is 1300031331112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2111331300031 - 235 = 2076971561663 is a prime.

It is a super-2 number, since 2×21113313000312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2111331299981 and 2111331300008.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2111331300037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055665650015 + 1055665650016.

It is an arithmetic number, because the mean of its divisors is an integer number (1055665650016).

Almost surely, 22111331300031 is an apocalyptic number.

2111331300031 is a deficient number, since it is larger than the sum of its proper divisors (1).

2111331300031 is an equidigital number, since it uses as much as digits as its factorization.

2111331300031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 2111331300031 its reverse (1300031331112), we get a palindrome (3411362631143).

The spelling of 2111331300031 in words is "two trillion, one hundred eleven billion, three hundred thirty-one million, three hundred thousand, thirty-one".