Base | Representation |
---|---|
bin | 11110101110010101001… |
… | …001101111001010111111 |
3 | 21110211201022022212122201 |
4 | 132232111021233022333 |
5 | 234043001303100111 |
6 | 4253533205052331 |
7 | 305352520640512 |
oct | 36562511571277 |
9 | 7424638285581 |
10 | 2111331300031 |
11 | 744457527358 |
12 | 2a12346b70a7 |
13 | 124136807b75 |
14 | 742907c0d79 |
15 | 39dc1de96c1 |
hex | 1eb9526f2bf |
2111331300031 has 2 divisors, whose sum is σ = 2111331300032. Its totient is φ = 2111331300030.
The previous prime is 2111331300017. The next prime is 2111331300037. The reversal of 2111331300031 is 1300031331112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2111331300031 - 235 = 2076971561663 is a prime.
It is a super-2 number, since 2×21113313000312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2111331299981 and 2111331300008.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2111331300037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055665650015 + 1055665650016.
It is an arithmetic number, because the mean of its divisors is an integer number (1055665650016).
Almost surely, 22111331300031 is an apocalyptic number.
2111331300031 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111331300031 is an equidigital number, since it uses as much as digits as its factorization.
2111331300031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 2111331300031 its reverse (1300031331112), we get a palindrome (3411362631143).
The spelling of 2111331300031 in words is "two trillion, one hundred eleven billion, three hundred thirty-one million, three hundred thousand, thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •