Base | Representation |
---|---|
bin | 11110101110010101001… |
… | …101001110010011110011 |
3 | 21110211201101001022101112 |
4 | 132232111031032103303 |
5 | 234043002021322003 |
6 | 4253533240423535 |
7 | 305352531465245 |
oct | 36562515162363 |
9 | 7424641038345 |
10 | 2111332214003 |
11 | 744457aa1001 |
12 | 2a1234a77bab |
13 | 124136a67b8c |
14 | 7429097c095 |
15 | 39dc202a3d8 |
hex | 1eb9534e4f3 |
2111332214003 has 2 divisors, whose sum is σ = 2111332214004. Its totient is φ = 2111332214002.
The previous prime is 2111332213999. The next prime is 2111332214039. The reversal of 2111332214003 is 3004122331112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2111332214003 - 22 = 2111332213999 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2111332214003.
It is not a weakly prime, because it can be changed into another prime (2111332214063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055666107001 + 1055666107002.
It is an arithmetic number, because the mean of its divisors is an integer number (1055666107002).
Almost surely, 22111332214003 is an apocalyptic number.
2111332214003 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111332214003 is an equidigital number, since it uses as much as digits as its factorization.
2111332214003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 2111332214003 its reverse (3004122331112), we get a palindrome (5115454545115).
The spelling of 2111332214003 in words is "two trillion, one hundred eleven billion, three hundred thirty-two million, two hundred fourteen thousand, three".
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