Base | Representation |
---|---|
bin | 110000000000011001001101… |
… | …011011001110101000011101 |
3 | 1000200120010221210020102110221 |
4 | 300000121031123032220131 |
5 | 210133202000114221341 |
6 | 2025013144415001341 |
7 | 62320610013156610 |
oct | 6000311533165035 |
9 | 1020503853212427 |
10 | 211133301320221 |
11 | 613011483a8105 |
12 | 1b81b06b509251 |
13 | 90a6a2850c977 |
14 | 3a1cc98ca6177 |
15 | 19620dd320ed1 |
hex | c0064d6cea1d |
211133301320221 has 16 divisors (see below), whose sum is σ = 263730618731520. Its totient is φ = 164831636701440.
The previous prime is 211133301320191. The next prime is 211133301320299. The reversal of 211133301320221 is 122023103331112.
It is a cyclic number.
It is not a de Polignac number, because 211133301320221 - 213 = 211133301312029 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211133301300221) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 28616599906 + ... + 28616607283.
It is an arithmetic number, because the mean of its divisors is an integer number (16483163670720).
Almost surely, 2211133301320221 is an apocalyptic number.
It is an amenable number.
211133301320221 is a deficient number, since it is larger than the sum of its proper divisors (52597317411299).
211133301320221 is a wasteful number, since it uses less digits than its factorization.
211133301320221 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 57233207244.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 211133301320221 its reverse (122023103331112), we get a palindrome (333156404651333).
The spelling of 211133301320221 in words is "two hundred eleven trillion, one hundred thirty-three billion, three hundred one million, three hundred twenty thousand, two hundred twenty-one".
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