Base | Representation |
---|---|
bin | 1001100110011110110010… |
… | …10111111111010011010111 |
3 | 2202202102101221002001010021 |
4 | 10303033121113333103113 |
5 | 10231410231232014221 |
6 | 112523211152210011 |
7 | 4306252004062306 |
oct | 463173127772327 |
9 | 82672357061107 |
10 | 21113411204311 |
11 | 6800169221358 |
12 | 244bb06839907 |
13 | ba1ca86c605a |
14 | 52dc7493043d |
15 | 26931ce12041 |
hex | 1333d95ff4d7 |
21113411204311 has 2 divisors, whose sum is σ = 21113411204312. Its totient is φ = 21113411204310.
The previous prime is 21113411204251. The next prime is 21113411204341. The reversal of 21113411204311 is 11340211431112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21113411204311 - 221 = 21113409107159 is a prime.
It is a super-2 number, since 2×211134112043112 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21113411204341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10556705602155 + 10556705602156.
It is an arithmetic number, because the mean of its divisors is an integer number (10556705602156).
Almost surely, 221113411204311 is an apocalyptic number.
21113411204311 is a deficient number, since it is larger than the sum of its proper divisors (1).
21113411204311 is an equidigital number, since it uses as much as digits as its factorization.
21113411204311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 25.
Adding to 21113411204311 its reverse (11340211431112), we get a palindrome (32453622635423).
The spelling of 21113411204311 in words is "twenty-one trillion, one hundred thirteen billion, four hundred eleven million, two hundred four thousand, three hundred eleven".
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